7x^2+144x-576=0

Solution for 7x^2+144x-576=0 equation:

7x^2+144x-576=0

a = 7; b = 144; c = -576;
Δ = b2-4ac
Δ = 1442-4·7·(-576)
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36864}=192$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(144)-192}{2*7}=\frac{-336}{14}
=-24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(144)+192}{2*7}=\frac{48}{14}
=3+3/7
$